Given an array of strings, group the words have the same letter-set together.

Use a sorted list to identify the words whether in the same set, and then use this list as a hash to make a 2-dimension list save the words making the same set together.

class Solution:
    def groupAnagrams(self, strs: List[str]) -> List[List[str]]:
        ans = []
        ordered_word_list = []
        index = 0
        sLen = len(strs)
        for i in range(sLen):
            ordered_word = "".join((lambda x:(x.sort(),x)[1])(list(strs[i])))
            find = 0
            for j in range(index):
                if ordered_word == ordered_word_list[j]:
                    find = 1
                    ans[j].append(strs[i])
            if find == 0:
                ordered_word_list.append(ordered_word)
                ans.append([strs[i]])
                index += 1
  
        return ans